remove last character in a string

[Former Member]

I have a variable with C type for example lv_c = 'xxxx#'. Now I want to remove the last character of this variable value? which function do I use? and how do I do that. Thanks!

[Former Member]

use: SHIFT lv_c.

[Former Member]

Hi,

just use offsetting..

data

w_temp like lv_c.

lv_c = 'xxxx#'.

w_temp = lv_c+0(4).

write: w_temp.

output is like this:

XXXX

lv_c+0(4) means it takes the first(i.e.from starting) 4 characters.based on this u can omitt or select the characters..just mention the offset value...

Regards

Kiran

Edited by: Kiran Saka on Feb 10, 2009 8:31 AM

[Former Member]

hi,

u can use n = strlen(lv_c) // u will get length of the string..

then lv_c = lv_c+0(n-1)... will fetch u the value except last character..

Rgds.,

subash

[former_member222860]

Hi,

here's the logic.

data: str type string value 'abcd#',    len type i.

len = strlen( str ).
len = len - 1.
str = str+0(len).

write:/ str.

[former_member770121]

thank u issue resolved.

[Former Member]

first find string length from function strlen

lv_len = strlen(lv_c)

lv_len = lv_len - 1

then make one more var of type lv_c lv_c1

lv_c1 = lv_c + 0(lv_len)

[Former Member]

Hi,

data w_i type i.

w_i = strlen( lv_c ).

subtract 1 from w_i.

write : lv_c+0(w_i).

This is working.

[Former Member]

Hi ,

You can use the following code It will solve the problem.-----

DATA : w_data(6) TYPE c VALUE 'ABCDEF'.
CONDENSE w_data NO-GAPS.
SHIFT  w_data RIGHT .
WRITE w_data.

Regards

Pinaki

[viquar_iqbal]

Hi

you can use

shift lv_c

condense lv_c

it should give you the remaining characters

Thanks

Viquar Iqbal

[Former Member]

Dear,

It is a special character.

To remove the special characters use below FM,

CONVERT_STREAM_TO_ITF_TEXT

Thanks and Regards,

[Former Member]

hi,

data:

w_str(5) type c value 'xxxx#'.

shift w_str by 1 places right.

write:/ w_str.

regards,

Mdi.Deeba

[Former Member]

Hi Anthony ,

Kindly go through this link below:

http://help.sap.com/saphelp_nw70/helpdata/en/9f/db999535c111d1829f0000e829fbfe/content.htm

Hope it helps

Regrds

Mansi

[Former Member]

Hi,

You can write this logic,

DATA:  lv_len TYPE i.
lv_len = STRLEN( lv_c ).
SUBTRACT 1 FROM lv_len.
lv_c = lv_c+0(lv_len). "Here last character will be removed

Regards,

Manoj Kumar P