String character replacement manipulation

[Former Member]

Hi, i'm new and have a question that I havn't seen answered on here yet.

I'm looking for a way to replace a string, ex: "You need # keyboard and # screens "

with something like " You need #1 keyboard and #2 screens".

Essentially, I need a way to loop through the string itself, and have an index to increase for each occurance of #, leaving a number after it.

The index increases by 1 for each occurance in the string, and resets when I put in a new string (i'm getting this string from a table value)

So make " There is # computer"

into "There is #1 computer"

and also "You need # keyboard and # screens "

into " You need #1 keyboard and #2 screens".

Thanks in advance!

[Former Member]

Hi Chris,

I new too and i've made this, i don't know if this is the kind of solution that you are looking for but i hope it helps.

REPORT  z_teste_brn_string.

TYPES: BEGIN OF ty_stab,

   field1(50) TYPE c,

END OF ty_stab.

TYPES: BEGIN OF ty_field,

   field1(50) TYPE c,

END OF ty_field.

DATA: it_stab TYPE STANDARD TABLE OF ty_stab.

DATA: it_field TYPE STANDARD TABLE OF ty_field.

DATA: v_string  TYPE string,

       v_string2 TYPE string,

       v_count   TYPE n,

       v_lines   TYPE n,

       v_final   TYPE string.

FIELD-SYMBOLS: <fs_stab> TYPE ty_stab.

FIELD-SYMBOLS: <fs_field> TYPE ty_field.

v_string  = 'there is # computer'.

v_string2 = 'You need # keyboard and # screens'.

APPEND v_string TO it_stab.

APPEND v_string2 TO it_stab.

LOOP AT it_stab ASSIGNING <fs_stab>.

   SPLIT <fs_stab> AT '#' INTO TABLE it_field.

   DESCRIBE TABLE it_field LINES v_lines.

   LOOP AT it_field ASSIGNING <fs_field>.

     v_count = v_count + 1.

     IF v_lines NE v_count.

       CONCATENATE <fs_field> '#' v_count INTO <fs_field>.

       CONCATENATE v_final <fs_field> INTO v_final.

     ELSE.

       CONCATENATE v_final <fs_field> INTO v_final.

     ENDIF.

   ENDLOOP.

   <fs_stab> = v_final.

   CLEAR: v_count,

          v_final.

   BREAK-POINT.

ENDLOOP.

Regards,

Bruno Magalhães

[Former Member]

Hi Chris,

Try the below code.

data: lv_hash(1) value '#',
        lv_spch(1) value '~',
        lv_cnt type i.
data: lv_char(2).

loop at itab.
replace all OCCURRENCES of lv_hash in itab-str with lv_spch replacement count lv_cnt.
do lv_cnt times.
lv_char = lv_hash && sy-index.
replace lv_spch in itab-str with lv_char.
enddo.

endloop.

Make sure the special character you use, will not be in the string.

Thanks,
Vamshi

[Former Member]

Thanks!

[Former Member]

Here is one more way to do it. It should work fine for ABAP release 702 and above.

1. DATA: text TYPE string VALUE 'You need to count # # and #',
2.       substring TYPE c VALUE '#'.
3. DO count( val = text
4.           sub = substring ) TIMES.
5.   text = replace( val   = text
6.                   sub   = substring
7.                   with  = substring && sy-index
8.                   occ   = sy-index ).
9. ENDDO.
10. WRITE text.

EDIT: sy-subrc check removed because it is not needed.

/.

Message was edited by: Manish Kumar

[renandacosta]

Great solution!

[Former Member]

really impressive solution...

i'll record that! =P